Tricky Trigometry

Geometry Level 3

sin 5 0 + sin 10 0 + sin 21 0 ( sin 2 5 ) ( sin 5 0 ) ( sin 10 5 ) = ? \large \dfrac{\sin 50^\circ+\sin 100^\circ+\sin 210^\circ}{(\sin 25^\circ)(\sin 50^\circ)(\sin 105^\circ)} =\, ?

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4 4 8 8 2 2 1 1

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2 solutions

Akshay Sharma
Mar 22, 2016

Let 2 A = 5 0 o 2 A=50^o , 2 B = 10 0 o 2 B=100^o , 2 C = 21 0 o 2 C=210^o

\quad\rightarrow A = 2 5 o A=25^o , B = 5 0 o B=50^o , C = 10 5 o C=105^o

Since, A + B + C = 18 0 o A+B+C=180^o ,We know that

s i n 2 A + s i n 2 B + s i n 2 C = 4 ( s i n A ) ( s i n B ) ( s i n C ) \boxed {sin 2 A+sin 2 B +sin 2 C=4(sin A)(sin B)(sin C)}

= = s i n 2 ( 2 5 o ) + s i n 2 ( 5 0 o ) + s i n 2 ( 10 5 o ) ( s i n 2 5 o ) ( s i n 5 0 o ) ( s i n 10 5 o ) \frac{sin 2(25^o)+sin 2(50^o)+sin 2(105^o)}{(sin 25^o)(sin 50^o)(sin 105^o)}

= = 4 ( s i n 2 5 o ) ( s i n 5 0 o ) ( s i n 10 5 o ) ( s i n 2 5 o ) ( s i n 5 0 o ) ( s i n 10 5 o ) 4\frac{(sin 25^o)(sin 50^o)(sin 105^o)}{(sin 25^o)(sin 50^o)(sin 105^o)}

= = 4 \boxed {4}

Umair Siddiqui
Mar 22, 2016

use 2 sinA sinB = cos (A-B) - cos (A+B) in the denominator.....then convert cos to sin

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