Trig!

Approach 1: We know that,
$\sin 45^o =\cos 45^o = \frac{1}{\sqrt 2}$
and, $\tan 45^o = 1$
So, $\sin 45^o \times \cos 45^o \times \tan 45^o =(\frac {1}{\sqrt 2} \times \frac {1}{\sqrt 2} \times 1)$
$\Rightarrow \sin 45^o \times \cos 45^o \times \tan 45^o = \frac{1}{\sqrt 2 \times \sqrt 2} =\frac{1}{2}= \boxed {0.5}$

Approach 2:
$\sin A \times \cos A \times \tan A = \sin A \times \cos A \times \frac{\sin A}{\cos A}$
Cancelling $\cos A$ with the $cos A$ in the denominator,
$\Rightarrow \sin A \times \cos A \times \tan A = (\sin A)^2$
Here $A=45^o$ , so,
$\Rightarrow \sin A \times \cos A \times \tan A = (\frac {1}{\sqrt 2})^2 = \frac{1}{2} = \boxed {0.5}$

Sin(45)xCos(45)xTan(45)= √2/2x √2/2x1= 1/2 meaning √2/2 and √2/2 multiplies together and solve as √2x √2= 2 (numerator) and 2 multiplies 2 =4(denominator). Then ulimately divide 2/4 and multiplies by 1 = 1/2