Trig ii

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If s e c 2 θ sec^2\theta + + s e c θ sec\theta = 2 =2 , then t a n 2 θ tan^2\theta 1 -1 is?

1 s e c θ 1-sec\theta s e c θ sec\theta - s e c θ sec\theta 1 + s e c θ 1+sec\theta

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1 solution

Aman Thegreat
Oct 2, 2017

We have to find t a n 2 θ tan^2\theta 1 -1

We know t a n 2 θ tan^2 \theta = = s e c 2 θ sec^2\theta 1 -1

t a n 2 θ tan^2\theta 1 -1 = s e c 2 θ sec^2\theta 2 -2

But we know s e c 2 θ sec^2\theta + s e c θ sec\theta = 2 =2

s e c 2 θ sec^2\theta = = 2 s e c θ 2-sec\theta

t a n 2 θ tan^2\theta 1 -1 = = s e c 2 θ sec^2\theta 2 -2

= = 2 s e c θ 2-sec\theta 2 -2 = = s e c θ \boxed{ -sec\theta }

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