Trig or Treat

Geometry Level 2

Simplify the expression

arctan ⁡ ( cos ⁡ 2 2 x + sin ⁡ 2 2 x ) . \arctan (\cos^{2}2x + \sin^{2}2x) .

sec ⁡ 2 x \sec^{2}x sec ⁡ 2 2 x \sec^{2}2x 0 0 4 5 ∘ 45^\circ 1 + x \sqrt{1 + x} for − 1 2 π < x < 1 2 π -\frac{1}{2} \pi < x < \frac{1}{2} \pi

View wiki
Brandon Stocks by Brandon Stocks , 45, USA

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Brandon Stocks
May 9, 2016

c o s 2 ( θ ) + s i n 2 ( θ ) = 1 cos^{2}( \theta ) + sin^{2}( \theta ) = 1 for all θ \theta

substituting θ = 2 x \theta = 2x

c o s 2 ( 2 x ) + s i n 2 ( 2 x ) = 1 cos^{2}( 2x) + sin^{2}( 2x ) = 1

a c r t a n ( 1 ) = 4 5 ∘ acrtan(1) = 45^\circ

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...