TRIGNOMETRIC TREASURE -> 2!
Algebra
Level
3
- Tan 1 * tan 2 * tan 3 .............tan 89 = A
- cos 1 * cos 2 * cos 3 .............cos 90 = B
- sin 0 * sin 2 * sin 3 .............sin 90 = C
- then (A + B + C)^3
- MORE FROM TRIGNOMETRIC TREASURE SERIES
The answer is 1.
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1 solution
=) 1. Ans.
By the Problem,[2nd Case]:-
=) 1/tan88 x tan88 [tan 88 will be canceled on both the sides by multiplying] =) 1.Ans.
Therefore, if we go on doing this for every ratios...we will come to the answer 1 for each case.