Trigonometric Treasure $\rightarrow 3!$

Algebra Level 3

If $\sec\theta + \cos \theta = \sqrt{5}$ , find $\sec^{2}\theta + \cos^{2} \theta$ .

1 solution

Shriniketan Ruppa
Jul 9, 2020

$\sec \theta + \cos \theta = \sqrt{5}$

On squaring the equation, we get

$\rightarrow$ $(\sec \theta + \cos \theta)^{2}$ = $(\sqrt{5})^{2}$

$\rightarrow$ $\sec^{2} \theta + \cos^{2} \theta + 2\sec \theta \cos \theta$ $= 5$

$\rightarrow$ $\sec^{2} \theta + \cos^{2} \theta + 2$ $= 5$

$\boxed{\sec^{2} \theta + \cos^{2} \theta = 3}$

this is an easy question ,

Razing Thunder - 11 months, 1 week ago

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Shriniketan Ruppa - 11 months, 1 week ago

nice question

Razing Thunder - 11 months, 1 week ago