Trigonometric differentiation

Calculus Level 1

y = ( sec ⁡ x + tan ⁡ x ) ( sec ⁡ x − tan ⁡ x ) y = (\sec x + \tan x)(\sec x - \tan x) . Find d y d x \dfrac{dy}{dx} .

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Saraswati Sharma by Saraswati Sharma , 23, India

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2 solutions

Md Zuhair
Oct 21, 2016

s e c 2 x − t a n 2 x = 1 sec^2x - tan^2x = 1 Now differentiation of 1 is 0 wrt x.

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Krishna Karthik
Mar 18, 2019

since sec ⁡ 2 ( x ) + tan ⁡ 2 ( x ) = 1 \sec^2(x)+\tan^2(x)=1 , d y d x \frac{dy}{dx} =0, because y is a constant.

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