If cot(θ)= 5/12 and 0°< θ <90°, what is tan(θ)? Write your answer in simplified, rationalised form tan(θ)= ?
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If 0 ° < θ < 9 0 ° , all the trigonometric functions (sine, cosine, etc.) are positive
Consider that c o t ( θ ) = ( t a n ( θ ) ) − 1 . Note that ( t a n ( θ ) ) − 1 = t a n − 1 ( θ ) , because t a n − 1 ( θ ) is the inverse function of t a n ( θ ) and ( t a n ( θ ) ) − 1 is a reciprocal function.
So, t a n ( θ ) equals to:
( t a n ( θ ) ) − 1 = 1 2 5
t a n ( θ ) = 5 1 2