For x , y ∈ R with 0 < x < 2 π such that
( cos x ) 2 y 2 ( sin x ) 2 y + ( sin x ) 2 y 2 ( cos x ) 2 y = sin 2 x
then find the value of y .
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Can you please put that in latex form. That would look more decent.
Problem Loading...
Note Loading...
Set Loading...
Let x = pi/4. Then we have sqrt(1/2)^(2y-.5y^2) + sqrt(1/2)^(2y-.5y^2) = sin(pi/2). So, sqrt(1/2)^(2y-.5y^2) = 1/2. So, 2y-.5y^2 = 2. So, y=2.