Trigonometry! #79

Geometry Level 2

If sin ⁡ A : cos ⁡ A = 4 : 7 \sin A : \cos A = 4 : 7 then find the value of 7 sin ⁡ A − 3 cos ⁡ A 7 sin ⁡ A + 2 cos ⁡ A \frac{7\sin A - 3\cos A}{7\sin A + 2\cos A} Enter the answer correct to three decimal places

This problem is part of the set Trigonometry .


The answer is 0.166.

Omkar Kulkarni by Omkar Kulkarni , 22, India

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1 solution

Rohit Krishna
Feb 2, 2015

1 Helpful 0 Interesting 0 Brilliant 0 Confused

sinA = 4k and cosA = 7k for some real k. Whence { 7sinA- 3cosA}/ {7sinA+2cosA] = 7k / 42k = 1/6 =0.1666..

Luiz Ponce Alonso Ponce - 6 years, 4 months ago

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