Trigonometry Crush 4

Geometry Level 3

The equation , where x is a variable , has real roots. Then the interval of "p" may be ...

(-π,0) (-π/2,π/2) (0,2π) (0,π)

Raj Rajput by RAJ RAJPUT , 25, India

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1 solution

Raj Rajput
Aug 14, 2015

3 Helpful 0 Interesting 0 Brilliant 0 Confused

Nice solution and again I like your handwriting!! keep it up.

But even if sinp is negative, the whole value can be positive.

Can't cos^2(p) dominate over 4(1-cosp)(sinp) when sinp is negative?

How will you justify that (0,pi) is the only interval??

Nelson Mandela - 5 years, 10 months ago

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(cosp)^2 will not be able to dominate over , take a value let p=4pi/3 then see :) and thanks for compliment :P

RAJ RAJPUT - 5 years, 10 months ago

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