Triangle Trouble
Geometry
Level
2
In fig. angle PQR =60° and ray QT bisects angle PQR . Seg BA is perpendicular to ray QP and seg BC is perpendicular to ray QR. If BC= 8 find perimeter of quadrilateral ABCQ
root 3
16+16 * root 3
12
17* root 3
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1 solution
Q C = tan 3 0 ∘ 8 = 8 3
A Q + Q C + C B + B A = 8 3 + 8 3 + 8 + 8 = 1 6 + 1 6 3