Trinometry

Geometry Level 3

If the value of i = 1 10 sin ( i π 11 ) \displaystyle \prod_{i=1}^{10} \sin\left( \dfrac{i\pi}{11} \right) equals A B \dfrac AB , where A A and B B are coprime positive integers, find A + B A+B .


The answer is 1035.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Mateus Gomes
Feb 9, 2016

k = 1 n 1 sin ( k π n ) = n 2 n 1 \prod_{k=1}^{n-1}\sin(\frac{k\pi}{n})=\frac{n}{{2}^{n-1}} n = 11 {\boxed{n=11}} k = 1 10 sin ( k π 11 ) = 11 2 10 = 11 1024 = A B \prod_{k=1}^{10}\sin(\frac{k\pi}{11})=\frac{11}{{2}^{10}}=\frac{11}{1024}=\frac{A}{B} A + B = 1035 \Large\color{#3D99F6}{\boxed{A+B=1035}}

https://www.youtube.com/watch?v=hQ532SjbxNo Here is a demostration of the identity

Juan Cruz Roldán - 7 months, 2 weeks ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...