Trip Expenses

Let's assume that, the number of total friends is $x$ and the total cost of the trip is $y$

From the question, we can conclude...

$y = 24x+6$ and $y=25x-3$

Comparing these two equations, we get...

$24x+6=25x-3 \Longrightarrow 25x-24x=6+3 \Longrightarrow x=9$

Substituting the value of $x$ in one of the equations, we get...

$y=24x+6 \Longrightarrow y= 24 \times 9 + 6 \Longrightarrow y=216+6 \Longrightarrow y=222$

Hence, the total cost of the trip is $\fbox {222}$ ...

24x+6=25x-3 so,x=9 Total cost of trip=25(9)-3=222

simple, the difference between them will be 9 dollars if there are 9 persons, so 9 x 25 - 3 = 222

The mathematical forms will be y = 24x + 6, and y = 25x - 3, where x = number of friends, y = total cost.

Then, we can substitute the y .

24x + 6 = 25x - 3.

So, there are x = 9 friends.

By choosing one equation (y = 24x + 6), and substituting x, we get y = 24×9 + 6 = 222 dollars

Let the number if friends in the group be 'x' and the total cost of trip be 'y'.

On forming the equations we have,

1. 24x = y - 6

2. 25x = y + 3

On solving the equations, we have, x = 9 and y = 222.

Therefore, the total cost of the trip (y) = 222$.

given: 24 dollars which is 6 dollars short and 25 dollars which is 3 dollars more so: 24/x-6:25/x+3 24(x+3)=25(x-6) 24x+78=25x-150 150+78=x 222=x

Suppose,the number of friends is x and the total cost is $y

so,24x+6=y and 25x-3=y From these two equations, 24x+6=25x-3 hence,x=9

so,y=24*9+6=222 so,the total cost is $222

Will call X the number of people who were up to the trip and the total price of Y On the first occasion, priced at £ 24, £ 6 failed to complete the full price, so:

Y = 24X - 6

On the second occasion, the price of 25 £ 3 £ exceeded the total price of the trip:

25X + Y = 3

formed an equation system

{Y = 24X - 6 ---> 1 {25X + Y = 3 --> 2

dividing by 2 1 we have:

25X / 24X = (y +3) / (Y - 6)

25Y - 24Y = 72 + 150

Y = £ 222

Assume the number of friends as n and the travel cost as C . We can work on two equations from this problem: C = 24n + 6 and C = 25n - 3 . Then, equalize the equations: 24n + 6 = 25n -3. The number of friends will be 9. Now, just substitute n by 9 in any of the equations (I chose the first one): C = 24x9 + 6; C = 216 + 6; C = $222. And there we have it!: The total cost was $222.

24x9=216 and 25x9=225 it shows that 222 is the no. from which 216 is 6 less and 225 is 3 more. so the actual trip cost is 222

There are 9 friends.

9*24=216 216+6=222

9*25=225 225-3=222

This can be seen as a system of equations . The two variables are:

• Number of friends (X)
• Total Cost of Trip (Y)

Y is the answer we are looking for. The question states

If they all contribute $24, then they would be $6 short

So the first equation is 24X=Y-6 The next part is

If they all contribute $25, then they would have $3 more than the total cost

So the next equation is 25X=Y+3

We then solve the first equation for Y:

24X=Y-6

24X+6=Y

So no we know the value of Y, which we plug into the next equation:

25X=Y+3

25X=(24X+6)+3

25X=24X+9

1X=9

X=9

Then we take the value of X and plug it back into the first equation

24(9)=Y-6

216=Y-6

222=Y

So the answer is $222

let total cost = t and number of friends = x

now, 24*x = t-6

and 25*x = t+3

solving the above equations, t = 222

6+3=9, 24 9=216, 25 9=225, there is shortage of $6 when each pay $24 therefore the cost is 216+6=222, or there is a remaining of $3 when each pay $25 therefore the cost is 225-3

no. of frnds= x

total cost of trip= y

therefore, we get- 24x = y-6 and,

25x = y+3

subtracting both equations, we get x=9

substituting the value in either one of the above equations, y=222

Let: n be the number of people in the group

x be the total cost of the trip.

$25 \times n = x + $3 (25 dollars each, collected from n persons is total cost + $3)

$24 * n = x - $6 (24 dollars each, collected from n persons is total cost - $6)

-------------------------- (subtract and eliminate x)

$1 * n = $9

   $9 = n * $1

   n   = $9 / $1

   n   = 9 persons

then, substitute n in one of the equations given, for example, take " $25 * n = x + $3 "

$25 * n = x + $3

$25 * 9 = x + $3 (n = 9)

$225 = x + $3

    x = $225 - $3

    x = $222

ex: total people : x

total cost : y

24x = y - 6

24x + 6 = y .... (eq 1)

25x = y + 3

y = 25x - 3 (eq 2)

sub eq 1 to eq 2

y = 25x - 3

24x + 6 = 25x - 3

x= 9

so that

y = 25 x - 3

y = 25 (9) - 3

y = 225 - 3

y = 222

24x+6 = 25x-3

x=9

24(9) + 6 = 222

25(9) - 3 = 222

therefore the total cost of the trip is $222

LET X BE THE TOTAL COST OF THE TRIP Y BE THE NO OF FRIENDS, THE THE TWO EQUATIONS FORMED ARE X=24Y+6 AND X=25Y-3 THEN BY SOLVING ABOVE TWO EQUATIONS WE GET NO.OF FRIENDS=9 AND TOTAL COST=222

Let "x" the number of friends and "y" the total cost of travel, so: 1 .24x=y-6 2.25x=y+3 Eq. 2 - Eq1 =>x=9 ; y =222

Se X= número de amigos e Y= custo da viagem, nós podemos afirmar que 24.X= Y-6 E 25.X= Y+3 ;RESOLVENDO isto temos {24.X= Y-6 *25 E {25.X=Y+3 *-24; ASSIM , {600x=25y-150 e { -600x=-24-72 ; cortando teremos 0=y-222 ; e enfim, y=222

Let the number of the friends in the group is x

And the total cost of the trip is y

Then we get the two equations:

$24x = y - 6$

and

$25x = y + 3$

Solving these two equation we get the value of $x = 9$ and $y = 222$

And we get the total cost of the trip is $222\$$

Let x represent the number of people. Let y represent the total cost.

25x = y + 3

24x = y - 6

Subtract equation B from A, thus getting that x = 9. Then, sub in 9 to solve for y which equals 222.

let no. of friends be x and the total cost of the trip be y. 24 x=y-6 , 25 x=y+3 solving both , we get y=222

24n+6=T ; 25n-3= T T= custo total

Sendo assim: 24n+6=25n-3

n=9

24*9+6=222

given if they contributed $24 each, they're in need of $6 . and if they would contribute $25 each.. they would be $3 more. so the difference from -$6 to +$3 would be equal to 9 , thus also the number of members contributing. hence ;

$24 * 9 + $6 = 222

same with

$25 * 9 - $3 = $222

let x = the number of persons in the group; y = total cost of the trip

from first condition, 24x + 6 = y

from second condition, 25x - 3 = y

therefor, y = 24x + 6 = 25x - 3

24x + 6 = 25x - 3

x = 9 (so there are 9 persons in the group)

substitute x = 9 into equation 24x + 6 = y

24(9) + 6 = y

y=222

Let T=total cost of the trip x=number of friends

Now,

(i) (24$)x=T-6$ [ so, x=(T-6$)/24$]

(ii) (25$)x=T+3

Through substituting eq. (i) to (ii), we get,

 (25$)[(T-6$)/24$]=T+3

 25$T-150$=(T+3)(24$)       (remark:we cannot let $*$=$^2 since $ is a currency, not a variable)

 25$T-150$=24$T+72$

 1$T=222$


 Hence, T=222

There are two equations: 24 n + 6 = T and 25 n - 3 = T. T => Total cost and n => Number of friends. So, 24 n + 6 = 25 n -3 => n = 9. Then, using it in one of the equacions (i'll choose the first): 24*9 + 6 = T => T = 222.

Let x represent the number of friends in this group. 24x + 6 = 25x - 3 x = 9 Therefore, total cost of the trip = 24x - 6 = 222

1. cost 1 = cost 2 cost 1 = 24x - 6 cost 2 = 25x + 3 where x is the number of person in the group substituting to 1.
2. 24x - 6 = 25x + 3 x= -9 ( there are no negative value of money) = +9 substituting the value of x to 2. 24(9) - 6 = 25(9) + 3 222=222