Triple divisors

Find the smallest positive integer that is simultaneously divisible by 35, 55, and 77.


The answer is 385.

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1 solution

Denton Young
Nov 4, 2017

35 = 5 * 7

55 = 5 * 11

77 = 7 * 11

So the number we seek is 5 * 7 * 11 = 385

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