∫ 0 2 π ∫ 0 2 π ∫ 0 2 π 1 − 3 1 ( cos x + cos y + cos z ) d x d y d z
If the closed form of the integral above can be expressed as:
4 A Γ ( 2 4 B ) Γ ( 2 4 C ) Γ ( 2 4 D ) Γ ( 2 4 E )
Find A + B + C + D + E .
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Yay! I did it! My brother couldnt!
According to the Wolfram MathWorld source provided by @Mark Hennings , "to obtain an entirely closed form, it is necessary to do perform some analytic wizardry." This is way over my head ...
But nice solution anyway!!
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This is basically one of the three famous Watson triple integrals ∫ 0 2 π ∫ 0 2 π ∫ 0 2 π 1 − 3 1 ( cos x + cos y + cos z ) 1 d x d y d z = 2 4 π 3 I 3 where I 3 = π 3 1 ∫ 0 π ∫ 0 π ∫ 0 π 3 − cos x − cos y − cos z 1 d x d y d z = 1 6 6 π 3 1 Γ ( 2 4 1 ) Γ ( 2 4 5 ) Γ ( 2 4 7 ) Γ ( 2 4 1 1 ) The proof is in the original 1939 paper, but some details can be found here .
This makes this integral equal to 4 6 Γ ( 2 4 1 ) Γ ( 2 4 5 ) Γ ( 2 4 7 ) Γ ( 2 4 1 1 ) and so the desired answer is 6 + 1 + 5 + 7 + 1 1 = 3 0 .