Triple metals

Two metal sticks A and B are fixed on the left wall in the above diagram. The lengths and the linear expansion coefficients of A and B are 3 L 3L , α \alpha and L L , 2 α 2\alpha , respectively. A third metal stick C with length 3 L 3L is fixed on the right joint bar on which the right end of B is also fixed. Suppose that there is a temperature change Δ T \Delta T which is the same for all of A , B and C , and the distance between the wall and C remains constant, which is L 0 L_0 as shown in the diagram. What is the linear expansion coefficients of the metal C ?

5 3 α \frac{5}{3}\alpha 3 4 α \frac{3}{4}\alpha 4 3 α \frac{4}{3}\alpha 3 5 α \frac{3}{5}\alpha

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1 solution

Sushant Samuel
Apr 19, 2014

In the given question :
Let coefficient of linear expansion of rod c be x;
{ Here change in temperature is represented by T }
For rod A ( Final Length ) : 3L(1+ aT)
For rod B ( Final Length ) : L(1+ 2aT)
For rod C ( Final Length ) : 3L(1+xT)

It is given that for all temperatures :
L(A) + L(B) - L(C) = Lo
3L + 3LaT + L + 2LaT - 3L - 3LxT = Lo

On differentiating the given equation :
3La + 2La - 3Lx = 0
5a=3x
x= 5a/3

why Lo is been change by 0?

Nicholas Lauw - 7 years, 1 month ago

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It is given in the question that for all change in temperature the difference in length is constant = Lo so change in Lo wrt. time would be zero

Sushant Samuel - 7 years, 1 month ago

before using this law Lf=L0+aT,we should assume that density /area is constant for each rod. because resistance = rho*L/A.

Wael Soudy - 6 years, 11 months ago

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