Three circles, each with a radius of , are mutually tangent to each other. The area enclosed by the three circles can be written as , where , and are positive integers, and is not divisible by a square of a prime. What is the value of ?
Details and assumptions
The enclosed area does not include the area within the circles.
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We connect the center of the circles and form an equilateral triangle with length 1 0 + 1 0 = 2 0 . The area of the triangle formed is 2 1 ⋅ 2 0 ⋅ 2 0 ⋅ sin 6 0 ∘ = 1 0 0 3 . The area that is within this triangle and within the circles is equal to 3 ⋅ ( 3 6 0 ∘ π ⋅ 1 0 2 ⋅ 6 0 ∘ ) = 5 0 π . Thus the area enclosed by the three tangent circles is 1 0 0 3 − 5 0 π . Hence a + b + c = 1 0 0 + 3 + 5 0 = 1 5 3 .