Triple Tangent Circles

Geometry Level 3

Three circles, each with a radius of 10 10 , are mutually tangent to each other. The area enclosed by the three circles can be written as a b c π a\sqrt{b} - c\pi , where a a , b b and c c are positive integers, and b b is not divisible by a square of a prime. What is the value of a + b + c a + b + c ?

Details and assumptions

The enclosed area does not include the area within the circles.


The answer is 153.

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1 solution

Arron Kau Staff
May 13, 2014

We connect the center of the circles and form an equilateral triangle with length 10 + 10 = 20 10 + 10 = 20 . The area of the triangle formed is 1 2 20 20 sin 6 0 = 100 3 \frac{1}{2}\cdot 20 \cdot 20 \cdot \sin 60^\circ = 100 \sqrt{3} . The area that is within this triangle and within the circles is equal to 3 ( π 1 0 2 6 0 36 0 ) = 50 π 3\cdot \left(\frac{\pi \cdot 10 ^2 \cdot 60^\circ}{360^\circ}\right) = 50\pi . Thus the area enclosed by the three tangent circles is 100 3 50 π 100\sqrt{3} - 50\pi . Hence a + b + c = 100 + 3 + 50 = 153 a + b + c = 100 + 3 + 50 = 153 .

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