Don't be tricked II

Algebra Level 2

Find the number of solutions for x x :

( x − 1 ) 2 ( x − 2 ) 2 ( x − 3 ) 2 ( x − 4 ) ( x − 5 ) ( x − 1 ) ( x − 2 ) ( x − 3 ) = 0 \frac { { (x-1) }^{ 2 }{ (x-2) }^{ 2 }{ (x-3) }^{ 2 }(x-4)(x-5) }{ (x-1)(x-2)(x-3) } =\quad 0


The answer is 2.

Brian Wang by Brian Wang , 19, USA

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1 solution

Brian Wang
Dec 13, 2015

Canceling out (x-1)(x-2)(x-3) on the top and bottom (taking into account that x cannot equal 1,2, or 3), we get (x-1)(x-2)(x-3)(x-4)(x-5)=0
Solving, we get x = 4,5 so the answer is 2

1 Helpful 0 Interesting 0 Brilliant 0 Confused

We can't cancel them out they can be 0 also.

Kushagra Sahni - 5 years, 6 months ago

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Fixed the solution.

Brian Wang - 5 years, 4 months ago

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