Trollathon 4-2

Level pending

Let $T = 2^{2^{2^{...^{2^{2}}}}}$ , where there are $2014$ twos.

Find the remainder when $T$ is divided by $8148143905337944345073782753637512644205873574663745002544561797417525199053346824733589504.$

(Scroll to the right as necessary to see the entire number. You should see a full stop at the end.)

2 solutions

Zi Song Yeoh
Apr 28, 2014

Actually that big number is $2^{302}$ . So, the answer is obviously $0$ .

I get it this is trollathon and I also guessed the answer as 0 , but how in the world is someone to get/comprehend that the big number is $2^{302}$

Amish Naidu - 7 years ago

True ! I agree :P

Aditya Raut - 7 years ago

Even I demand to know the same piece of information, and I am asking this in a long sentence because Brilliant is not allowing short replies...

Shabarish Ch - 6 years, 9 months ago

Wolfram Alpha ;)

Zi Song Yeoh - 6 years, 7 months ago

Noel Lo
Apr 14, 2015

OMG!! I randomly guessed 0!!!!