True either way

We know that two times of $EN$ is a multiple of 100, implying $EN$ is 50. We know that if the carry over from $R+T+T$ is 1, then $O$ is 9 and $I$ is 0, resulting in a repeat. Thus the carry over from $R+T+T$ is 2, $O$ is 9 and $I$ is 1. At the same time, we know $T$ must be sufficiently large for $R+T+T$ to exceed 20. As 9 is taken, try 8. Also, try 7 for $R$ . We get $X$ is 4. We find that it works and we have 2 consecutive numbers 2 and 3 for $F$ and $S$ respectively. It follows that $Y$ is 6.

Clearly EN = 50. R + 2T is at least 19. The rest is simple cut and try.