True or False?

True or False?

There exists integer solutions ( x , y , z ) (x, y, z) to ( x y ) 3 + 3 ( y z ) 2 + 5 z x = 2017 (x-y)^3+3(y-z)^2+5|z-x|=2017 .

False True

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1 solution

Linkin Duck
Mar 16, 2017

Since ( x y ) + ( y z ) + ( z x ) = 0 (x-y)+(y-z)+(z-x)=0 is an even number, the set [ ( x y ) , ( y z ) , ( z x ) ] [(x-y),(y-z),(z-x)] contains 3 even numbers or 1 even number and 2 odd numbers, which always leads to the fact that M = ( x y ) 3 + 3 ( y z ) 2 + 5 z x M=(x-y)^3+3(y-z)^2+5|z-x| must be even, hence M M cannot be 2017 2017 .

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