True or False? #1

Calculus Level 4

Which of the followings are true?

A. Let f ( x ) = x 2 + 1 f(x)=x^2+1 , then f ( x ) f ( x ) \sqrt{f(x)-f'(x)} is differentiable in ( , ) . (-\infty,~\infty).

B. For all positive numbers a a , function f ( x ) = x a f(x)=x^a that is defined over all reals is differentiable in ( , ) . (-\infty,~\infty).

C. If polynomials f ( x ) f(x) and g ( x ) g(x) satisfy f ( g ( x ) ) = g ( f ( x ) ) f(g(x))=g(f(x)) and f g , f\neq g, at least one of f f and g g is an identity function.


This problem is a part of <True or False?> series .

None of them Only A Only B Only B and C Only C and A Only A and B All of them Only C

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Boi (보이)
Jul 18, 2017

A.

f ( x ) = 2 x f'(x)=2x and f ( x ) f ( x ) = x 2 2 x + 1 = x 1 \sqrt{f(x)-f'(x)}=\sqrt{x^2-2x+1}=|x-1| .

Therefore the expression is not differentiable at x = 1 x=1 .

FALSE \therefore~\boxed{\text{FALSE}}


B.

(counterexample)

f ( x ) = x 1 3 f(x)=x^{\frac{1}{3}} is not differentiable at x = 0 x=0 , because f ( x ) = 1 3 x 2 3 f'(x)=\dfrac{1}{3x^{\frac{2}{3}}} .

FALSE \therefore~\boxed{\text{FALSE}}


C.

(counterexample)

If f ( x ) = 2 x f(x)=2x and g ( x ) = 3 x g(x)=3x , f ( g ( x ) ) = 6 x = g ( f ( x ) ) f(g(x))=6x=g(f(x)) , but neither f f nor g g is an identity function.

FALSE \therefore~\boxed{\text{FALSE}}


Therefore, none of them are true.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...