Find the shortest path

Geometry Level 3

There’s a cylinder as follows. Its two undersides are solid surfaces. When putting it on the table, its base circumference is 48 48 and its height is 7 7 .

True or false? If an ant wants to go from F F to H H (Crawling on the surface of the cylinder), its shortest route is 25 25 .

False True

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1 solution

Edward Christian
Aug 15, 2019

Now we have 2 routes. One is F H FH , the other is F G G H FG-GH . We can get F H = ( 48 2 ) 2 + 7 2 = 25 FH=\sqrt{(\dfrac{48}{2})^2+7^2}=25 . The other route F G G H = 48 π + 7 22.3 < 25 FG-GH=\dfrac{48}{\pi}+7\approx 22.3<25 . So the answer is flash.

NOTE: To further explore, for a cylinder with height 7 7 and base circumference x x , we construct the function f ( x ) = ( x 2 ) 2 + 7 2 = x 2 4 + 49 × 4 4 = x 2 + 196 4 , g ( x ) = x π + 7 f(x)=\sqrt{(\dfrac{x}{2})^2+7^2}=\sqrt{\dfrac{x^2}{4}+\dfrac{49\times 4}{4}}=\sqrt{\dfrac{x^2+196}{4}},g(x)=\dfrac{x}{\pi}+7 and graph it,

I'm not doubting your solution, but how come we consider FG - GH to be a possible path in this case?

Deva Craig - 1 year, 9 months ago

it's just another way to get from F to H

Ishaan Ivaturi - 1 year, 9 months ago

This question really punked me as expected. I calculated ONE of the paths to be 25. But I got punked... Great question

Krishna Karthik - 1 year, 4 months ago

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