Truly hard problem
Algebra
Level
pending
what is a and b, integers, such that x=a^b with a>3 and b>1 we have :
x = 10b+a
Where P is the integer part. Give a+b where a+b < 51
The answer is 7.
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1 solution
5^2 = 20 + 5 is a solution so we have 5+2=7