Truncated harmonic series?

Let Y Y be a discrete random variable having the following probability density function,

P ( Y = y ) = 1 y , P(Y =y) = \dfrac1{y} ,

where y = n , n + 1 , n + 2 , y = n, n+1, n + 2 ,\ldots and n n is a positive integers . What is the number of digits of n n ?

This is an impossible scenario 4 3 5

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1 solution

Gonçalo Vieira
Oct 24, 2019

An important property of discrete random variables is that the sum of the probabilities of its possible values is equal to 1. So:

1 n \frac{1}{n} + 1 n + 1 \frac{1}{n+1} + 1 n + 2 \frac{1}{n+2} + ... = 1

but the left side is the harmonic series without the first n-1 terms. Noticing that:

k = 1 a ( k ) \sum_{k=1}^{\infty} a(k) converges if and only if k = n a ( k ) \sum_{k=n}^{\infty} a(k) converges for any n N n\in\N

As the harmonic series diverges, for any n N n\in\N the right side will diverge, so it is impossible.

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