Truncated!

Geometry Level 3

If the number of hexagonal faces in a truncated tetrahedron is a a and the number of triangular faces is b b , Find the value of

2 a + 2 b \large{2^{a}+2^{b}}


The answer is 32.

Md Zuhair by Md Zuhair , 20, India

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2 solutions

X X
May 15, 2018

2 4 + 2 4 = 32 2^4+2^4=32

4 Helpful 0 Interesting 0 Brilliant 0 Confused
Blan Morrison
May 11, 2018

For every face on the original tetrahedron, there is a hexagonal face on the truncated version. For every vertex on the original version, there is a triangular face on the truncated version.

4 faces = 4 hexagons = a 4 \text{ faces} = 4 \text{ hexagons} = a 4 vertices = 4 triangles = b 4 \text{ vertices} = 4 \text{ triangles} = b 2 4 + 2 4 = 2 × 2 4 = 2 5 = 32 2^4+2^4=2\times 2^4=2^5=\boxed{32}

2 Helpful 0 Interesting 0 Brilliant 0 Confused

But, why is this a Chemistry question?

Aryan Sanghi - 3 years ago

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@aryan sanghi I agree with you.....!! But now it is tagged under Geometry section....

Aaghaz Mahajan - 3 years ago

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