Determine the force in the top chord of the truss (Member CD) under the given load conditions. An external load of 5 KN is applied horizontally at node D. A vertical load of 10 KN is applied downward at node C. Express your answer in Newtons.
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Let A v = vertical reaction at A and B v = vertical reaction at B
Summation of moments at A = 0:
B v ( 1 4 ) = 1 0 ( 4 ) + 5 ( 6 )
B v = 5 k N
Summation of moments at B = 0:
A v ( 1 4 ) + 5 ( 6 ) = 1 0 ( 1 0 )
A v = 5 k N
Cut a section thru CD to FE. Take summation of moments at F = 0:
C D ( 6 ) = A v ( 4 )
C D ( 6 ) = 5 ( 4 )
C D = 3 . 3 3 k N = 3333.33 Newtons-compression
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