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x 5 + y 2 + z 2 x 5 − x 2 + y 5 + z 2 + x 2 y 5 − y 2 + z 5 + y 2 + x 2 z 5 − z 2
Let x , y and z be positive real numbers satisfying x y z ≥ 1 , find the minimum value of the expression above.
The answer is 0.
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Minimum value of xyz>/=1 is 1 at say x=1 y=1 z=1 Now put this in the eqn u get 0+0+0=0