Terminated factorials

Number Theory Level 2

( 100 ! − 100 ) ( 99 ! − 99 ) ( 88 ! − 88 ) ⋅ ⋅ ⋅ ( 23 ! − 23 ) \large (100!-100)(99!-99)(88!-88) \cdot \cdot \cdot (23!-23)

What will be the sum of last two digits of the number above?


The answer is 0.

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Yash Saxena by Yash Saxena , 20, India

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1 solution

Yash Saxena
May 12, 2015

As the last two digits of(100!-100) will be 100 so on multiplication with all the numbers the last two digits of the numbers will be 00 and the sum of 0+0 is 0

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