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Algebra Level 4

If f ( x ) f(x) be a monic polynomial of degree four and satisfying f ( 1 ) = 10 , f ( 2 ) = 20 , f ( 3 ) = 30 f(1)=10,f(2)=20,f(3)=30 .

If f ( 12 ) + f ( 8 ) = 3968 ω f(12)+f(-8)=3968ω , find ω ω .

Details

Monic polynomial means polynomial whose leading coefficient is 1.


The answer is 5.

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2 solutions

Shivam Jadhav
Jan 16, 2016

According to the given condition we can write f ( x ) = ( x a ) ( x 1 ) ( x 2 ) ( x 3 ) + 10 x f(x)=(x-a)(x-1)(x-2)(x-3)+10x Therefore , f ( 12 ) = ( 11 ) ( 10 ) ( 9 ) ( 12 a ) + 120 f(12)=(11)(10)(9)(12-a)+120 f ( 8 ) = ( 11 ) ( 10 ) ( 9 ) ( 8 + a ) 80 f(-8)=(11)(10)(9)(8+a)-80 f ( 12 ) + f ( 8 ) = ( 11 ) ( 10 ) ( 9 ) ( 12 a + 8 + a ) + 40 f(12)+f(-8)=(11)(10)(9)(12-a+8+a)+40 f ( 12 ) + f ( 8 ) = ( 11 ) ( 10 ) ( 9 ) ( 20 ) + 40 f(12)+f(-8)=(11)(10)(9)(20)+40 f ( 12 ) + f ( 8 ) = 3968 ( 5 ) f(12)+f(-8)=3968(5) ω = 5 \huge{\boxed{ω=5}} .

Krutarth Patel
Feb 8, 2021

I solved it the same way as Shivam, but I don't think we can get a unique polynomial that satisfies f ( i ) = 10 i , i { 1 , 2 , 3 } f(i) = 10i, i \in \{ 1, 2, 3 \}

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