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1 solution
1 2 x 3 − 3 ( 2 x 3 + 4 x − 1 ) − 5 x + 7
= 1 2 x 3 − ( 6 x 3 + 1 2 x − 3 ) − 5 x + 7
= 1 2 x 3 − 6 x 3 − 1 2 x + 3 − 5 x + 7
= 1 2 x 3 − 6 x 3 − 1 2 x − 5 x + 3 + 7
= 6 x 3 − 1 7 x + 1 0