Try this Challenge if you dare?

The bob of mass m , charge q is circulating in a vertical circle of radius R , with the help of a massless inextensible string. if the maximum speed of the bob is V , then the period of revolution is T 1 { T }_{ 1 } . If an electric field of magnitude (mg/q) is setup which makes an angle 60 degree with upward vertical.

Again the bob is circulating in same circle and its maximum speed is V , the period of revolution being T 2 { T }_{ 2 } .

Find 95 *( T 1 T 2 \frac { { T }_{ 1 } }{ { T }_{ 2 } } )?

Data

\bullet m = 5 kg,

\bullet g=10

\bullet R= 2m

\bullet q = 1 C

Additional challenge

\bullet Solve this without actually solving for the time periods!!!


The answer is 95.

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1 solution

Deepanshu Gupta
Nov 2, 2014

The thing which differ in 2nd case is that the equilibrium position is shifted by an angle of 60 degree ( By using Concept of effective gravity )

So Time period is remain same in both situation since it is independent of equilibrium position !!

Nice put up question @Tushar Gopalka and I suggest u to add dummy values of such as maximum velocity , mass , Charge etc. So that Problem becomes more good .

Yeah, nice thought....

Tushar Gopalka - 6 years, 7 months ago

I did the same, but actually solving for the time periods would be difficult though...

Aalap Shah - 6 years, 2 months ago

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