NASA is testing their space robot on a flat plane. They gave it instructions to:
- Move forward 3 miles
- Turn 90 degrees left
- Move forward 4 miles
- Turn 90 degrees left
- Move forward 3 miles
How far away will the robot be from its starting point?
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Mars isn’t flat. Wouldn’t it being a spheroid affect the surface and distance overall?
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But the robot is tested in the laboratory, it havent arrive in mars yet :)
The question said Flat plane
What a nonsensical solution.
I was considering it is not flat, but the description explicitly states that - "flat plane"
The description of the problem was changed after I reported the problem, but it's so long after that, that I guess it doesn't even matter. This site has thousands of errors.
Let's say that the robot is facing North. He will head North 3 miles, then West 4 miles and then South 3 miles. Hence, it ends up being West 4 miles of the starting point.
Dear Sir How can I post a question on this app?
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U have to use the computer site to post questions
Thanks for the visual diagram! I think that everything is a bit easier to understand if you have a visual. c:
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are u talkin about me? :P
Please see my questions too. Hope You ll like
Just a displacement computation stuff :)
Assuming a flat, featureless plain with no obstacles or pitfalls.Or possibly outer space, it being a "space robot", but that's not what the picture shows.
Not necessarily. If he started at the north pole he would end up where he started. Calvin, only If he started 1.5 miles south of the Equator, this would be true.
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This is not true unless the earth has a circumference of 12 miles! if the rover started at the north pole and moved south 3 miles then turned west the rover is told to move forewords 4 mile not west 4 Miles. to move west 4 miles, you would have to keep turning to face west. if you travailed foreword you will start pointing more south the further you went. you would not end up back at the north pole. but assuming you follow the curvature of the earth you would be slightly less than 4 miles from your starting point where ever on earth you started from.
Approximate solution... must neglect curvature.
I used the tiles of my floor for this one, hehehehe.
Hey, that's a creative way to visualize this problem! :)
Tania see my post i drew the tiles here :P Ur idea is also cool!
if you compute it, it will move 3 miles and move back 3 miles because it turn 180 degrees
Just calculate the displacement..
The answer is true assuming the space robot is going in a single plane. If the robot is going down the side of a mountain the answer could vary. Min 0 - max 10.
let us consider it's in point a it moves 3 miles forward and turns left and moves 4 miles and again moves 3 miles this has constructed 3 sides of a rectangle then it must be 4 miles to complete that rectangle!
McDonnell goes forward 3 miles, turns 90 degrees left, goes forward 4 miles, turns 90 degrees left, and goes forward 3 miles again. Restating it from the point of view of the robot's original orientation, it went forward 3 miles, left 4 miles, and back 3 miles. The forward 3 miles and back 3 miles cancel out to make a total displacement of 4 miles left.
The robot's path creates a rectangle. Opposite sides of a rectangle are the same. Therefore, the answer is 4. Since the question asks how far away it is, which implicitly means the "shortest distance"( i.e. a line connecting the location your robot is in after completing the last instruction and its initial location), and not the distance traveled by the robot, the answer is 4 (instead of 10). Although, if the question had a restriction which did not allow the robot to complete a closed path, the answer would be 10.
since it is moving 3 miles forward and then turning 90 degrees and then 4 miles and 90 degrees and then 3 miles we can see that it is forming a rectangle and hence the last side is 4 miles.hence the answer is 4
Acctually it makes rectangle and problem ask for the big magnitude of the rectangle.
The movement of the robot describes a rectangle. The stopped part distances 4 miles left of the starting point.
straight 3 miles then left 4 miles and again returning back towards starting point by 3 miles..! So we travel 4 miles away from the starting point at the first left turn
4 miles from starting point, if displacement is considered
Easy answered 4 miles from starting point
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