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1 solution
Notice that 6 + 2 6 + 2 3 + 2 2 = ( 2 + 3 + 1 ) 2 and 5 − 2 6 1 = ( 3 − 2 ) 2 ) 1 .
Now our expression becomes, ( 2 + 3 + 1 ) 2 − ( 3 − 2 ) 2 1 = 2 + 3 + 1 − 3 − 2 1 = 2 + 3 + 1 − 1 ( 3 + 2 ) = 1 .