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Without considering the order, how many different pairs of positive integers add up to make 1000?

As an explicit example, 6 is equal to 1 + 5 , 2 + 4 , 3 + 3 1 + 5, 2 + 4, 3 + 3 . So there are exactly 3 different pairs of positive integers that add up to make 1000.


The answer is 500.

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3 solutions

By writing the sums as: 1 + 999, 2 + 998, 3 + 997, ... , 499 + 501, 500 + 500. It is clear that the number of different pairs is five hundred.

3ash ya m3allem !

Mohamed Ashraf - 6 years, 6 months ago
Jingyang Tan
Mar 2, 2015

6 div 3 =2
1000 div 2= 500

Pretty much

Braelyn Tebo - 5 years, 6 months ago

For odd number "x", number of pairs= [x/2] and for even number "x", number of pairs= x/2

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