Try without a calculator 2

$(-2^{-2})^{-2} = (-2)^{4} = \boxed{16}$

$\large{(-2^{-2})^{-2}=(-\frac{1}{2^2})^{-2}=\frac{1}{(-\frac{1}{4})^2}=\boxed{16}}$

$(-2^{-2})^{-2} = (-2)^4 = 2^4 = \boxed{16}$

first : solve the archs ... = (1/4)^-2 (turned the value) second step : we will turn it again to remove the minus , so it's 4^2 =16

(-2)^(-2)^-2=(-2)^4=16

(-2^{-2})^{-2} = \frac{1}{-2^{-4}} = -2^{4} = -2 \times -2 \times -2 \times -2 = \boxed {16}

(-2^(-2))^(-2)= 4^2=16

First solve the number in the brace the number is (-2)power -2 that means (1/-2) power 2 so answer in brace is (-1/4) so next problem in the question is (-1/4)power-2 that means 4 power 2 answer finally is 16

(-2^-2^-2 = (-2)^4 =16