Tsunami

A tsunami is a giant wave generated by an earthquake. Consider a tsunami wave far away from its source that has λ = 2 k m \lambda=2km wavelength in water that is d = 1 k m d=1km deep. The amplitude of the wave is A = 1.5 m A=1.5m . This wave is barely noticable, since the largest slope (the angle relative to the horizontal) is s = 2 π A / λ 0.2 7 s= 2 \pi A/\lambda\approx 0.27^{\circ} . A ship could easily sail over the wave. As the tsunami approaches the shore, the amplitude increases. Estimate the amplitude of the wave in 10m deep water.

Hint: The speed of the wave is related to the depth of the water by v = g d v=\sqrt{gd} , where g g is the acceleration of gravity (this is true if the wavelength is longer than the water depth). Similar to other harmonic oscillations, the energy the wave is proportional to the amplitude-squared. The energy density, defined as the energy in a unit area of water, integrated over the depth, is ϵ = C ρ g A 2 \epsilon= C \rho g A^2 , where ρ \rho the density of water and C C is a numerical constant of order of 1. The energy flux carried by the water is Φ = v ϵ \Phi= v \epsilon . We may assume that the energy flux is constant, whereas the velocity and the amplitude changes.

Bonus: How long will it take for the wave to pass under the ship in 1 k m 1km deep water?

2m 10m 5m 20m

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1 solution

Laszlo Mihaly
Nov 15, 2017

Since the quantity v ϵ v \epsilon is constant, we can write g d A 2 = c o n s t \sqrt {gd} A^2 = const and therefore A 1 4 d 1 = A 2 4 d 2 A_1^4d_1=A_2^4d_2 . This is known as the "Green's law for shallow water waves". The amplitude will be

A 2 = ( d 1 d 2 ) 1 / 4 A 1 = 4.74 m A_2=\left(\frac {d_1}{d_2}\right)^{1/4} A_1= 4.74m

At this height the amplitude is comparable to the water depth, and the wave is very close to crushing. That can be very dangerous to ships. That is why in a tsunami situation ships try to go out to deep water (although they do not have much time to do that, since a wave moves really fast).

The speed of the wave out in the open ocean is v = g d = 140 m / s 500 k m / h 300 m p h v=\sqrt{gd}= 140 m/s \approx 500km/h \approx 300mph and it takes for the full 2km wave about 14 seconds to pass under the ship. Closer to shore, in water depth of 10m, the velocity is 10m/s (36 km/h, about 20 miles per hour). Note that the tsunami wave rarely gets extremely high (like 10-15 m), because of the 1/4 power law in the equation. It can still be very destructive, especially if the conditions (the depth profile of the ocean) causes the wave to focus to a certain area. There is also a huge amount of displaced water that gets pushed to shore - that phenomenon is well beyond the simple wave motion we discussed here.

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