turamater!!!
Geometry
Level
4
AB is the diameter of the circle of radius 10 a point on the circle such that arc BC = 5π/3 the bisector of angle ACB cuts the circle at D .Find CD??? Answer up to 2 decimal places
The answer is 17.32.
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1 solution
Let the circle centre be O & Angle BOC = θ. Then 10*θ=5π/3 . Hence, θ=π/6 from which we infer that Angle COB=75°. Therefore, CD = 20cos(75-45)
= 17.32