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The above is the elliptical orbit of a planet of the sun. If this planet sweeps $\frac{1}{12}$ of the orbital area in $30$ days, then what is its orbital period?

720 days 180 days 240 days 360 days

2 solutions

Anish Puthuraya
Feb 14, 2014

Kepler's Law states that a Planet sweeps equal area in equal time.
Thus,
if it sweeps $\displaystyle\frac{1}{12}$ area in $\displaystyle 30$ days, then,
it will sweep a full orbital area in $\displaystyle T = 30\times 12 = \boxed{360days}$

Kalidoss Murugan
Mar 29, 2014

if the planet sweeps 1/12 orbital area in 30 days. for complete orbit 1/12 Part = 30 days then 1 part = 30 x 12 = 360 days

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