You have 12 identical-looking coins, one of which is fake - either heavier or lighter than the rest (it is not known). The only scale you have to use is a simple balance and no measure weights.
How many measurements do you need to perform to find the fake coin?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
I had once seen this question so i remembered the answer. But I don't know the method correctly. Please correct my solution. I don't know if it's correct. We divide 12 coins in 3 groups of 4. Now we take two groups and put them in the weighing pan. Case 1: We get that both the pans are balanced. Then the third group surely contains the fake coin. We now remove the 8 coins present in the pan and put 2 coins of the third group into the pans. Case 1.1 If they balance then remove only one of them and put another of that same group. If again they balance then the remaining coin is fake. Or else the third coin is fake. Case 1.2 If they didn't balance then remove one of the coins and put another coin. If they balance then the removed coin is fake. If they don't then the coin which was not removed first is fake. I couldn't work further properly. Please help