Twisted Triangle

Geometry Level 2

Given that A B C \triangle ABC is equilateral with side 1 unit, A P = B R = C Q = 1 5 AP=BR=CQ=\dfrac 15 and perimeter of the colored triangle is a × a b a \times \sqrt{\dfrac {a}{b}} , find a + b a+b , where a a and b b are relatively prime.

"The general problem of finding perimeter of colored triangle when A P = B R = C Q = m ; m < 1 AP=BR=CQ=m;m<1 appeared in the Chennai Mathematical Institute Undergraduate Entrance Exam 2018"


The answer is 10.

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