Two equations

Algebra Level 2

If both a + b = c a + b = c and a 2 + b 2 = c 2 a^{2} + b^{2} = c^{2} are true and a < b a < b , what is the value of a + ( b c ) a + (b - c) ?


The answer is 0.

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2 solutions

Vilakshan Gupta
Mar 16, 2018

Squaring a + b = c a+b=c \implies a 2 + 2 a b + b 2 = c 2 c 2 + 2 a b = c 2 2 a b = 0 a^2+2ab+b^2=c^2 \implies c^2+2ab=c^2 \implies 2ab=0

Either a a or b b must be 0 0 , but since a < b a<b , we can have a = 0 a=0 .

Then if a = 0 a=0 , this implies b = c b=c .

Then b c = 0 b-c=0 and hence a + ( b c ) = 0 a+(b-c)=\boxed{0}

If b = 0 b=0 and a < 0 a<0 , then we have a = c a=c and hence a + ( b c ) = a c = 0 a+(b-c)=a-c=\boxed{0}

Nice solution. Since we are not given conditions on a , b a,b we could also have b = 0 b = 0 , (making a < 0 a \lt 0 ), but this would just lead to a = c a = c and a + ( b c ) = a c = 0 a + (b - c) = a - c = 0 as well.

Brian Charlesworth - 3 years, 2 months ago

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Thanks. I have edited the solution.

Vilakshan Gupta - 3 years, 2 months ago
Ivan Jambrešić
Oct 18, 2018

a + ( b c ) = a + b c a+(b-c)=a+b-c

c = a + b c=a+b

a + b c = a + b ( a + b ) = a + b a b = 0 a+b-c=a+b-(a+b)=a+b-a-b=0

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