If both a + b = c and a 2 + b 2 = c 2 are true and a < b , what is the value of a + ( b − c ) ?
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Nice solution. Since we are not given conditions on a , b we could also have b = 0 , (making a < 0 ), but this would just lead to a = c and a + ( b − c ) = a − c = 0 as well.
a + ( b − c ) = a + b − c
c = a + b
a + b − c = a + b − ( a + b ) = a + b − a − b = 0
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Squaring a + b = c ⟹ a 2 + 2 a b + b 2 = c 2 ⟹ c 2 + 2 a b = c 2 ⟹ 2 a b = 0
Either a or b must be 0 , but since a < b , we can have a = 0 .
Then if a = 0 , this implies b = c .
Then b − c = 0 and hence a + ( b − c ) = 0
If b = 0 and a < 0 , then we have a = c and hence a + ( b − c ) = a − c = 0