Given that f ( x ) = sin x and g ( x ) = x / 1 0 . If x 1 , x 2 , . . . , x n are the values of x for which f ( x ) = g ( x ) , then find the maximum possible value of n − 1 ⌊ x 1 ⌋ − ⌊ x 2 ⌋ + ⌊ x 3 ⌋ − ⌊ x 4 ⌋ + ⋯ ± ⌊ x n ⌋ − 1 .
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How you got those 7 solutions except 0 ?
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I used a spreadsheet and plotted y = sin x and y = 1 0 x . We only need an approximate solutions because we only need the greatest integer values.
by drawing graph of both sinx and X/10 and their comman points are solution
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There are 7 solutions for sin x = 1 0 x .
They are: x = 0 , ± 2 . 8 5 2 , ± 7 . 0 6 8 , ± 8 . 4 2 3
⇒ ⌊ x ⌋ = − 9 , − 8 , − 3 , 0 , 2 , 7 , 8
The maximum possible value is:
7 − 1 − ( − 9 ) − ( − 8 ) − ( − 3 ) + 0 + 2 + 7 + 8 − 1 = 6 3 6 = 6