Two large Fibonacci numbers

Consider the Fibonacci numbers :

  • F 0 = 0 F_0 = 0
  • F 1 = 1 F_1 = 1
  • F n = F n 1 + F n 2 F_n = F_{n-1} + F_{n-2} for n > 1 n > 1

ln ( F 8046 ) ln ( F 8045 ) = ? \ln (F_{8046}) - \ln (F_{8045}) = \text{ } ?

(Provide your answer to three decimal places)


The answer is 0.481.

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1 solution

Jordan Cahn
Jan 14, 2019

ln ( F 8046 ) ln ( F 8045 ) = ln ( F 8046 F 8045 ) ln ( ϕ ) F n + 1 F n ϕ as n , where ϕ is the Golden Ratio. 0.4812 \begin{aligned} \ln(F_{8046}) - \ln(F_{8045}) &= \ln\left(\frac{F_{8046}}{F_{8045}}\right) \\ &\approx \ln(\phi) && \color{#3D99F6} \frac{F_{n+1}}{F_n} \to \phi \text{ as } n\to\infty\text{, where }\phi\text{ is the Golden Ratio.} \\ &\approx \boxed{0.4812} \end{aligned}

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