Two pendulums

In the two pictures above, [A] is a spring pendulum installed on a frictionless floor, and [B] is a simple pendulum installed on a ceiling. Which of the following statements is correct? (Ignore all frictional forces, and suppose that the angle θ \theta of the simple pendulum is very small.)

a) The directions of the forces acting on [A] and [B] are opposite to the directions of the displacements.

b) The greater the masses of the two pendulums, the greater the periods of the harmonic oscillations.

c) If we install these two pendulums on the moon where the gravitational acceleration is smaller than on the earth, then only the period of [B] gets longer.

a) and b) a) and c) a) only b) and c)

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2 solutions

Dhruv Shah
May 26, 2014

False...

a, b, c are right...as 'w' proportional to (1/m) thus T prop to m

Shahbaz Khan
Apr 24, 2014

bcz simpie pendulum (B) depend on length and grevity T=2 Pi (l/g)^1/2 so g less on moon T longer bt spring pendulum T=2 pi (m/k)^1/2

no but how do u select two options in one click??

Meera Yadav - 7 years, 1 month ago

statement A is incorrect. since when the pendulum swings from right to left the component of the gravitational force mg sin(theta) is in the same direction as that of the displacement.

Meera Yadav - 7 years, 1 month ago

B is correct, in pegas T = 2Pi (m/k)^1/2

Yodji Fufuri - 7 years, 1 month ago

a n c r right as T of A is independent of mass

ysakh prasad - 7 years, 1 month ago

only (a) is correct as

in spring also, T= 2pi(m/k)^1/2 which is equal to

T= 2pi(m/F/x)^1/2 (as k=F/x) = 2pi(x/g)^1/2 (as F=mg)

Therefore, I am not happy with this answer and you should consider my point and if I am not correct, tell me why.

Kartik Sharma - 7 years ago

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