Two people with the same birthday

Probability Level pending

You and a friend are standing outside a room containing 25 people, all of whom are strangers to both of you. He says, "I will give you $20 if there are not two people in that room who share a birthday (month and day). Otherwise, if there are, you pay me $20."

Do you take that bet? (In other words, is there a greater than or less than 50% probability that two people in the room share a birthday?)

I do not take the bet, Chances are I will lose $20 I take the bet. Chances are I will win $20.

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1 solution

David Welch
Mar 10, 2015

In a room of 25 people, there are 25 24 2 = 600 2 = 300 \frac { 25•24 }{ 2 } =\frac { 600 }{ 2 } =300 unique pairs of people. (Want to change your answer yet?)

Furthermore, there is a 364 365 \frac { 364 }{ 365 } probability that a given pair of people have different birthdays.

Therefore, the probability that all people in the room have different birthdays is ( 364 365 ) 300 { (\frac { 364 }{ 365 } ) }^{ 300 } , which evaluates to about .439.

In a room containing 25 people, the likelihood that there are not 2 people who share a birthday is 43.9%. You would not be wise to accept this bet.

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