Two spheres

In what ratio will a charge split up between two conductive spheres connected with a long thin wire ?

Details and assumptions:

  • The radii of the two spheres are r 1 = 7 cm r_1 = 7 \space \text{cm} and r 2 = 3 cm r_2 = 3 \space \text{cm} .
  • The wire is long and thin enough, so that it doesn't disturb the even distribution on both spheres, the charge splits up so that their potential is the same.
  • Give your ratio as the larger sphere to the smaller sphere.
  • Give your answer to 2 decimal places.


The answer is 2.33.

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1 solution

André Hucek
Oct 18, 2017

We see that

Q 1 4 π ε ε 0 1 r 1 = Q 2 4 π ε ε 0 1 r 2 \displaystyle \frac{Q_1}{4 \pi \varepsilon \varepsilon_0} \frac{1}{r_1} = \frac{Q_2}{4 \pi \varepsilon \varepsilon_0} \frac{1}{r_2} From which

Q 1 Q 2 = r 1 r 2 = 7 3 = 2.33 \displaystyle \frac{Q_1}{Q_2} = \frac{r_1}{r_2} = \frac{7}{3} = \boxed{2.33}

So the charge splits up in the ratio of the radii: 70 % 70\% on the larger sphere, 30 % 30\% on the smaller sphere.

You might want to specify whether the ratio is q1/q2 or q2/q1. People might get the answer wrong for a silly reason otherwise.

Steven Chase - 3 years, 7 months ago

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Given that r 1 = 7 \color{#3D99F6}r_1 = 7 and r 2 = 3 \color{#D61F06}r_2 = 3 , and that Q 1 Q 2 = r 1 r 2 \frac{Q_1}{Q_2} = \frac{\color{#3D99F6}{r_1}}{\color{#D61F06}{r_2}} , it is unlikely to be switched, but i will edit it, thank you for your feedback.

André Hucek - 3 years, 7 months ago

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