Two stones in air and water

When two stones were held apart in air, the gravitational force between them was observed to be 5 N 5 \text{ N} .

If the stones are immersed in water, and the distance between them is kept constant, then what is the gravitational force between the stones now?

Less than 5 N 5 \text{ N} Equal to 5 N 5 \text{ N} Greater than 5 N 5 \text{ N}

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Pranshu Gaba
Jun 6, 2016

The gravitational force between two objects is given by F = G m 1 m 2 r 2 F = \dfrac{Gm_1 m_2}{r^2} . Here, m 1 m_1 , m 2 m_2 are the masses of the objects; r r is the distance between them; and G G is the universal gravitational constant. None of these depend on the medium the objects are placed in.

Therefore, when the stones are placed in water, the gravitational force between them is still 5 N 5 \text{ N} . _\square

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...