Logic - al - jabr

Algebra Level 4

Let c c and d d be integer constants such that the polynomial f ( x ) = x 3 8 x 2 + c x d f(x) = x^3 - 8x^2 + cx - d has three distinct positive integers as its roots. Find f ( 1 ) f(1) .


The answer is 0.

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1 solution

Otto Bretscher
Feb 29, 2016

Since the sum of the three distinct positive roots of f ( x ) f(x) is 8 (by Viete), one of these roots has to be 1. Note that 2 + 3 + 4 > 8. 2+3+4>8. Thus f ( 1 ) = 0 f(1)=\boxed{0} .

Amazing solution!! I was trying to find all possible roots which turned out to be ( 1 , 2 , 5 ) (1,2,5) and ( 1 , 3 , 4 ) (1,3,4) , though in both the cases the answer was 0 0 , and it's obvious because in both the cases, the 1 1 is a root. But this thought didn't strike at that time. An upvote from me!!!

Raushan Sharma - 5 years, 3 months ago

This is really a very clever solution. I spent time on this problem on computing the value of c d c-d which is required in computing f ( 1 ) f(1) . However , I was unable to find it , so I resorted to trial and error.

Nihar Mahajan - 5 years, 3 months ago

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